$\lim_{x\to0}\left(\frac{12\sin\left(x\right)-12x}{x^3}\right)$
$\frac{3x^3-3x^2}{-3x}$
$\:0,75+1,272$
$\lim_{x\to1}\left(\frac{x^3-3x+2}{1+x+\ln\left(x\right)}\right)$
$x^2-59x+58$
$2\sqrt{1-x}=\sqrt{16-3x}-1$
$\frac{2^{-3}}{2^{-10}}$
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