$\frac{dy}{dx}\left(xy^2+tan^{-1}\left(x+y\right)=\frac{\pi}{4}\right)$

$2\left(-16+7\right)+3\left(15+5-6-4\right)$

$\frac{8x^6+2x^9+4x^3}{-4x^3}$

$\frac{dy}{dx}=\frac{\left(x^2+4-x\right)^{\frac{1}{2}}-x}{2}$

$\int x ^ { - 45 } d x$

$4\cdot\frac{6}{8}$

$2.4\cdot1.2$