$\frac{1-\cos\left(2x\right)}{\tan^2x}=2\cos^2x$
$\int\frac{y^3+5y}{\left(y^2+1\right)^2}dx$
$\lim\:_{x\to\:6}\left(\frac{x^2-36}{x-6}\right)$
$\frac{dy}{dx}=\frac{\left(x-3\right)y^8}{x^2\left(9y^5-y\right)}$
$-5t\:+\:10\:=25$
$\frac{5x+21}{-4}>1$
$y^2-7y+30$
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