$\left(x+3y\right)\left(4a+12x\right)$
$3\sqrt[3]{m^2}\:$
$-18\:\:\left(-8\:-\:24\right)\::\:2$
$25a-70a+49$
$-\frac{48}{\left(-20+8.4\right)}-4.\left(2.4+5\right)$
$\frac{y^2-x^2}{x-y}$
$\int\frac{10}{5x+1}dx$
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