$3x^3y=x^3-x\frac{dy}{dx}$

$2\left(-3y\right)\left(-xy\right)$

$\left(2a+5c\right)^2$

$csc\left(\theta\:\right)-cot\left(\theta\:\right)=\frac{sin\left(\theta\:\right)}{1+cos\left(\theta\:\right)}$

$\frac{ln\sqrt{a^3\sqrt{b^5\sqrt{c^7}}}}{4\:}$

$\frac{dy}{dx}-4y\left(x\right)+8=0$

$csc^2x=cotx+1$