$\frac{36^4-121^6}{6a^2+11p^3}$
$\left(2-x\right)\left(1\right)$
$\left(x^3-7x^2+5x\right)-\left(9x^4-4x^2+8x+12\right)\:$
$\frac{36^2-9}{6m+3}$
$114x^4\:y\:+34y$
$5y+7+x-5+4x+3y$
$1^3$
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