$4^x=16$
$\lim_{x\to\frac{\pi}{2}}\left(\frac{\left(\frac{\pi}{2}\right)-x}{\cos\left(x\right)}\right)$
$\lim_{x\to-\infty}\left(\frac{6}{e^x}\right)$
$\left(x+2\right)\left(x-3\right)>2-x$
$x^2\:-25x+125$
$5\left(x-7\right)^2$
$5=3x^2-12x+9$
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