$x^3-3x^2+2x$
$\int\frac{\left(4x+13\right)}{x^2+3x-10}dx$
$3\left(3c+5\right)+5\left(3c-8\right)$
$23\cdot\left|-10\right|$
$8\log_{10}\left(20\right)$
$\left(-5m^2\right)\cdot\left(-m^5\right)$
$\frac{1}{x+5}=\frac{2}{7x}$
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