$\left(7x^2+9x+3\right)+\left(5x^2-2x+1\right)$
$-\left(9x+2\right)$
$3b^2-5b-2$
$4x^3-9x$
$4-8\sin^26x$
$\frac{2}{\sin\left(3\right)}$
$\frac{\sin\left(q\right)+\tan\left(q\right)}{\cos\left(q\right)+1}=\tan\left(q\right)$
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