$3y+36\le10$
$\left(2y^3\right)^3$
$\left(z+6\right)^2$
$\frac{dy}{dt}=-\:\:\frac{t}{\left(y-2t\right)}$
$\left(-32\right)-\left(+9\right)-\left(-17\right)-\left(+28\right)$
$\int\frac{t^{3}-8t+1}{\left(2t\right)^{4}}dt$
$\sec\left(x\right)-\cos^2\left(x\right)$
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