$\int\frac{x+4}{x^2+x}dx$
$\left(8a^2-9b^3\right)^2$
$x2\:+\:6x\:+\:6$
$25a^4-4b^2$
$\frac{3}{4}xyz-xyz+xyz-\frac{1}{2}$
$\frac{\left(1+sec\left(x\right)\right)}{sin\left(x\right)+tan\left(x\right)}=csc\left(x\right)$
$\frac{8x^5+4x^3+8x^2+4x+16}{2x^3+x^2+3}$
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