$\arctan\frac{18}{6}$
$-74\:-\:\left(-20\right)$
$\left(x^{\frac{2}{3}}-y^{\frac{2}{3}}\right)^5$
$\frac{dy}{dx}=\frac{1}{\sqrt{\left(1-x^2\right)}}$
$\left(1.4y\right)^3$
$\left(3j-2y+1\right)^2$
$x^2+2xy+y^2=\left(x+y\right)^2$
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