$\int\frac{1}{\left(1+x\right)\left(1+x^2\right)^2}dx$
$-\:\left(\:-\:\left(\:-\:\left(\:-33\:\right)\:\right)\:\right)$
$4a^2-2b$
$-10\cdot\left(-7\right)$
$\frac{1-\left(a+n\right)^2}{1-\left(a+n\right)}$
$\frac{sin\left(x\right)^2}{cos\left(x\right)^2}-sin\left(x\right)^2$
$\frac{dv}{df}+3v=0$
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