$\left(\frac{e^x}{1+x^2}\right)\left(e^x\right)$
$\lim_{x\to0}\left(\frac{ln\left(x\right)}{e^x+8}\right)$
$x^2-16x+81$
$-10x^2-25x+60$
$2x+5+3x$
$\sec\left(x\right)^2\:+\:36$
$x^4+x^2-\frac{8}{x-3}$
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