$x^2-4x+3\le0$
$\frac{3x^4+2x^2-5x+3}{x+3}$
$\int\cot\left(x\right)\left(2+\ln\left(\sin\left(x\right)\right)\right)dx$
$\frac{d}{dx}\left(6x-4y^2=0\right)$
$29+\left(-332\right)+1611$
$4x^2-16x-2$
$\frac{x^2+3x-4}{x^2-2x+8}$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!