$\frac{-2x+4}{x-1}=\frac{3}{x+1}$

$\int_0^2\left(\frac{\left(\sqrt{x}+8\right)^2}{12\sqrt{x}}\right)dx$

$\sqrt{\left(x^2-2x-3\right)^2}\le\:5\sqrt{\left(x^2-4x-3\right)^2}$

$\cos\left(8x\right)\cdot\cos\left(5x\right)$

$10x=-x^2-25$

$\frac{x^{7-4}-y^{8-2}}{x^{1-2}+y^{1-1}}$

$\frac{3}{2}2.5$