$\:\left(a+b+3\right)\left(a+b+4\right)$
$x'=\frac{1}{x^3}$
$w^6a^6\cdot9w^4a^4$
$\frac{x^4+2x^3-6x^2+5}{x+3}$
$2\:x\:+\:1\:>\:7$
$x^3+4x^2-10x+12$
$\lim_{x\to8}\left(\frac{\sqrt{x+1}-3}{x^3-61x-24}\right)$
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