$\left(2f+8\right)\left(2f-5\right)$
$x^2+2x+0$
$\frac{4\left(x-4\right)}{x^2+2x-8}=\frac{4}{x+4}$
$\int3x^2+3x^2+1x^3+2x^2+2x+1dx$
$y'-xy=x^3$
$x^2-25x+84=0$
$\int\left(sin\left(x\right)\cdot\left(6+cos\left(x\right)\right)^8\right)$
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