$x^2+12x+1$
$\lim_{x\to0}\left(\frac{ln\left(x^2+8x\right)}{ln\:x}\right)$
$1+sin\left(\pi+x\right)\cdot cos\left(x+\frac{3\pi}{2}\right)$
$6cos\left(2t\right)=6\:sin^2\left(t\right)+2$
$-8y=-3y-15$
$\frac{\left(x-2\right)}{8}^3$
$-4^{-1+e^0}$
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