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Solve the quadratic equation $\frac{11}{10}t^2-\frac{6}{5}+\frac{3}{10}=0$

Step-by-step Solution

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Final Answer

$t=\sqrt{\left(\frac{9}{11}\right)},\:t=-\sqrt{\left(\frac{9}{11}\right)}$
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Step-by-step Solution

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Divide $11$ by $10$

$\frac{11}{10}t^2-\frac{6}{5}+\frac{3}{10}=0$

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$\frac{11}{10}t^2-\frac{6}{5}+\frac{3}{10}=0$

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Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 11/10t^2+-6/5+3/10=0. Divide 11 by 10. Divide -6 by 5. Subtract the values \frac{3}{10} and -\frac{6}{5}. We need to isolate the dependent variable , we can do that by simultaneously subtracting -\frac{9}{10} from both sides of the equation.

Final Answer

$t=\sqrt{\left(\frac{9}{11}\right)},\:t=-\sqrt{\left(\frac{9}{11}\right)}$

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Solve for tFind the rootsSolve by completing the squareSolve by quadratic formula (general formula)Find break even pointsFind the discriminant

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Function Plot

Plotting: $\frac{11}{10}t^2-\frac{6}{5}+\frac{3}{10}$

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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Main Topic: Quadratic Equations

The quadratic equations (or second degree equations) are those equations where the greatest exponent to which the unknown is raised is the exponent 2.

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