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$\frac{10x^{-3}\left(4x^2\right)^2}{4\left(5x\right)}$

Final answer to the exercise

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Other solved exercises

$-5<\frac{4-3x}{3}$

$\frac{dy}{dx}=\frac{x}{y^4}$

$\frac{t^{20}}{t^5r^3}$

$x^2+0.0000151x-0.00000484$

$5\cdot2^3-9\cdot2+85$

$\frac{64^4}{64^3}$

$4^{x-2}=16^{x-4}$
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