$5x^2+2y^2-3-\left(x^2-2y^2+3\right)+\left(3x^2-6\right)$
$100\cdot0.01$
$\int_{-\infty}^1\left(\frac{x}{x^2+3}\right)dx$
$\frac{d}{dx}\left(\frac{3x-y}{x+2y}\right)$
$6cos^2x-7cosx+2=0$
$6x+5>4x+11$
$4x^4+16y^4$
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