$\int6\:x^4\:dx$
$x^3+y^3=4$
$cos^2\left(u\right)\left(sec^2\left(u\right)-1\right)=sen^2\left(u\right)$
$\lim\:_{x\to\:-\infty\:}\left(1-\frac{2}{x}\right)^{1-x}$
$\frac{z^5-3z^3-7z}{z-2}$
$\frac{x}{\sqrt{x+4}}$
$\int_0^8\left(\left(3x-2\right)\sqrt[3]{\left(x-5\right)}\right)dx$
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