Exercise
$\frac{1-\tan^2\left(x\right)}{\tan\left(x\right)+1}$
Derivative of this function
$\frac{d}{dx}\left(\frac{1-\tan\left(x\right)^2}{\tan\left(x\right)+1}\right)=\frac{2\left(-\tan\left(x\right)-1\right)\tan\left(x\right)\sec\left(x\right)^2+\left(-1+\tan\left(x\right)^2\right)\sec\left(x\right)^2}{\left(\tan\left(x\right)+1\right)^2}$
See step-by-step solution
Integral of this function
$\int\frac{1-\tan\left(x\right)^2}{\tan\left(x\right)+1}dx=\frac{x\left(1-\tan\left(x\right)^2\right)}{\tan\left(x\right)+1}+C_0$
See step-by-step solution