$cos4\theta\:=8sen^4\theta\:-8sen^2\theta\:+1$
$\left(3x-6\right)\left(4x+3\right)$
$\lim_{x\to2}\left(\frac{5-x}{x^2-4x+4}\right)$
$\int6e^{2x}dx$
$m^2\:.\:m^4\:.\:m^3$
$\sqrt{1.66666}$
$\frac{10}{x^2+5x-6}$
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