$-2x+\frac{dy}{dx}=0$

$\int\frac{x-6}{\left(x+3\right)\left(2x-5\right)}dx$

$\frac{dy}{dx}\left(x^3y-2xy^2=1\right)$

$-3\int_0^{2\pi}\left(cos^2\left(x\right)\cdot\:sin^2\left(x\right)\right)dx$

$y^2+8y+2$

$\left(x+7\right)^2=-6$

$\frac{\left(x\:-\:sin\:x\right)}{x}$