$1+tan^2\left(x\right)=sec^3\left(x\right)\cdot\:\:cos\left(x\right)$
$\frac{\cos x\:+\:1}{\sin\left(x\right)}=cot\frac{x}{2}$
$3x-18<5x-37$
$\frac{d^3-a^3}{d^2-a^2}$
$\int\frac{4sin\left(x\right)}{2+cos\left(x\right)}dx$
$csc^2x-4=0$
$-5d+3c-4d$
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