$x^2+2x+5\ge0$
$1248+736-\left(-828\right)$
$a^3-3a^2b+5ab^2$
$\lim_{x\to\frac{\pi}{2}}\left(\frac{1-\tan\left(1\right)\left(x\right)}{\cos\left(2\right)x}\right)$
$\frac{3x^4-2\left(2\right)x^3-10x^2-2\left(2\right)^2x+6}{x+1}$
$\left(3x^3\right)\left(-2y^3x^3\right)\left(-5y^{-3}x^4\right)$
$y^{''\:}-4y^{'\:}+4y=0$
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