$3\left(x-2\right)+2x\left(x+3\right)>\left(x+4\right)\left(x+5\right)$
$20x^2-7x-120$
$10\:-\:\left(-15\right)\:+\:3\:-\:8\:$
$\int\left(\frac{1}{\left(\sqrt{2+4x}\right)}\right)dx$
$-\left(-30\right):6+5+24:\left(-3\right)$
$-8-15\cdot\left(2+-9\right)$
$3c-5\ge9$
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