$8\cdot111$
$\sqrt{36x^8}y^6$
$\frac{8x^5+4x^3+x^2+10x+16}{2x^3+x^2+3}$
$\left(\frac{w^8}{w}\right)^{\frac{1}{14}}$
$\frac{dx}{dy}\left(y-1\right)x^2=y+1$
$\lim_{x\to\infty}\left(8x\ln\left(x\right)+4\right)$
$\frac{d}{dx}x^{7x+8}$
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