$6z-11\ge7$
$a^2+2-7+2a+5$
$\frac{\left(2x^3+x^2-x+4\right)}{x^2+x}$
$\left(2x^4-3x^2y^6\right)^3$
$\frac{dy}{dx}\left(\frac{xy^3}{1+y^2}=\frac{192}{17}\right)$
$56,478\:x\:28,45$
$\left(y^3+2y\right)+\left(2x+3xy^2\right)\frac{dy}{dx}=0$
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