$\lim_{x\to-2}\left(\frac{x^2-4}{2x+4}\right)$

$64u^2+16u+1$

$1=\tan\left(x\right)\sin\left(x\right)^2+\cos\left(x\right)^2$

$\frac{5.6\cdot10^{-6}}{2\cdot10^{-4}}$

$\left(-b^3+8a\right)^2$

$\lim_{x\to-\infty}\left(\frac{\sqrt{4x^6+x^2}}{x^3+1}\right)$

$\frac{d}{dx}x^{ln9x}$