$\left(3x^2-4\right)\left(3x^2-4\right)$

$18x+5-10$

$4x-\frac{2}{9}x+\frac{x}{3}$

$h\left(x\right)=\left(x^4-6x^2-2x\right)^3$

$\left(\sec^4\left(x\right)-\tan^4\left(x\right)\right)-\sec^2\left(x\right)$

$\left(8y^2+4x^3\right)^2$

$\int_{-2}^2\left(\sqrt{4-y^2}\right)dy$