$\left(13x+12y\right)^2$
$\left(4x\right)\left(6x\right)-3x\cdot9x$
$x^4+p^2-q;\:x=2,p\:=3,q=9$
$6x\:-9y\:+21yz\:-14xz\:$
$\left(z^2-3z+3\right)-2\left(z-1\right)$
$\lim_{x\to\infty}\left(\frac{x^2-4x+7}{x-6}\right)$
$xy+y=\left(xy\right)^3$
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