$\int\frac{x^2+1}{\left(x-4\right)\left(x-3\right)^2}dx$

$\lim_{x\to0}\left(\frac{-e^x+1}{xe^x}\right)$

$20\left(x\:+\:33\right)\:=\:900$

$y=ln\left(\frac{x}{sin\:x}\right)$

$g\left(x\right)\:=\:4\left(x^2-3x\right)^3$

$a^2b^2\left(a^2b^2+a^3b^3\right)$

$\frac{dy}{dx}=\frac{x-y+6}{3x-3y+4}$