$2x^3+4x+2x-8$
$\left(x^2+2x+1\right)\left(4x^2+8x+16\right)$
$\int\frac{x}{x^2-2x+3}dx$
$\lim_{x\to0}\cot\left(x\right)-\frac{1}{\sin\left(x\right)}$
$\int_{-1}^3\left(e\right)dx$
$+\:3\:-\:5\:+\:2\:-\:10\:+\:4\:-\:7\:+\:1$
$\left(x+2\right)\left(x+3\right)v^2-16$
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