$\lim_{x\to\infty}\left(\frac{\log\left(x+1\right)^2+1}{\log\left(x\right)^2+1}\right)$

$x+14=121$

$e^{2x}-12e^x+35=0$

$5x^3-44x^2+61x+14$

$\int_0^{.5}\left(\frac{\left(1-cosx\right)}{x^2}\right)dx$

$\int\frac{7x+6}{x^2-3x}dx$

$\left(\frac{2x^{-3}}{xy^2}\right)^{-2}$