$2\csc^2x=4$
$b^3\cdot b^3$
$\lim_{x\to0}\left(\frac{\frac{1}{\left(x+h\right)^2}-\frac{1}{x^2}}{h}\right)$
$\int_{-\infty}^0\left(ze^z\right)dz$
$4\cdot\left(-1111\right)$
$\frac{\left(x-a\right)}{b}+\frac{\left(x-b\right)}{a}=2$
$\frac{2}{\left(1-x\right)^2}>-1$
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