$4x-\left\{3y+\left[4x-\left(3y-4x\right)-3y\right]-4x\right\}-3y$
$12y^2+4y^2+15y^3+33y^3+12$
$\int\frac{\ln\left(x^3\right)}{x^3}dx$
$-18x+8=-x^2$
$\left(-8\right)\cdot0,25$
$\frac{6+5}{2}-\frac{6-5}{2}$
$\left(10\right).\left(-12\right):\:\left(+6\right)$
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