$\frac{3x}{10}+\frac{x+12}{8}>\frac{2x-2}{6}+11$
$\left(2-3x\right)\left(1-x\right)^4$
$\left(x+4\right)\left(x-d\right)$
$\int\frac{x-5}{\left(x^2+1\right)\left(2x+1\right)}dx$
$-2x^4+4x^3+2x^2+2x-3;\:x=-2$
$4^2\cdot5^2$
$\lim_{x\to\infty}\left(\frac{x^2-3x+2}{e^x}\right)$
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