$-7-8x-4+4x$
$\frac{d}{dx}\:x^3-3x^2y^4+y^3=6x+1$
$\int_{\frac{8}{27}}^1\left(\frac{10x^{\frac{4}{3}}-8x^{\frac{1}{3}}}{x^2}\right)dx$
$\lim_{x\to\infty}\left(\frac{6x^3+2x-1}{3x^2-4}\right)$
$c^2+10c+8=0$
$16^{\frac{5}{4}}-256^{\frac{3}{4}}$
$3y^2+5y=12$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!