$sin\left(8x\right)\:=\:2\:sin\left(4x\right)\:cos\left(4x\right)$
$3\sqrt{2}^2$
$\left(2b\right)^9$
$\int\frac{8x^2+41x-6}{x^3+6x^2}dx$
$6g^2+7g$
$\frac{\left(x+7\right)}{x^2+5}=1$
$\left(-2-2y\right)^2$
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