$2-4^2$
$\lim_{x\to-\infty}\left(\frac{3-x^3}{x^2}\right)$
$\int\frac{e^x}{\left(e^x-5\right)\left(e^x+6\right)}dx$
$204+200$
$\left(4x^3+12\right)^2$
$8x-2\left(x-5\right)=x+25$
$3x^2-4x-2x^2-4x$
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