$a^2-8a+12=0$

$\left(x+1\right)^2\cdot\left(2x\right)$

$\frac{\left(cos\left(8t\right)+cos\left(4t\right)\right)}{sin\left(8t\right)-sin\left(4t\right)}$

$196x^2-225y^{12}$

$\int\frac{1}{x^2+8x+80}dx$

$\left(4a^24\right)^2$

$\frac{dy}{dx}=e^{-11t},\:y\left(0\right)=16$