$\frac{\left(x^2+4x+100\right)}{x+5}$
$\left(x+9\right)^3$
$\lim_{x\to\infty}\left(\frac{\left(x\right)}{x^2-x}\right)$
$\frac{0,2+1.1}{0.6}-1$
$\frac{1+tan\left(x\right)}{1-tan\left(x\right)}=1+\frac{1+tan\left(x\right)}{1-tan\left(x\right)}$
$a^2+16a-64$
$25n^2-121m^2$
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