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# Simplify $\frac{1}{2}\cdot \left(128-84\right)+128-84-\frac{1}{2}\cdot \left(128-84\right)$

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asinh
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##  Final answer to the problem

$44$
Got another answer? Verify it here!

##  Step-by-step Solution 

How should I solve this problem?

• Choose an option
• Write in simplest form
• Prime Factor Decomposition
• Solve by quadratic formula (general formula)
• Find the derivative using the definition
• Simplify
• Find the integral
• Find the derivative
• Factor
• Factor by completing the square
Can't find a method? Tell us so we can add it.
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Subtract the values $128$ and $-84$

$\frac{1}{2}\cdot \left(128-84\right)+44-\frac{1}{2}\cdot \left(128-84\right)$

Learn how to solve addition of numbers problems step by step online.

$\frac{1}{2}\cdot \left(128-84\right)+44-\frac{1}{2}\cdot \left(128-84\right)$

Learn how to solve addition of numbers problems step by step online. Simplify 1/2(128-84)+128+-84-1/2(128-84). Subtract the values 128 and -84. Subtract the values 128 and -84. Subtract the values 128 and -84. Divide 1 by 2.

##  Final answer to the problem

$44$

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

SnapXam A2

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9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

###  Main Topic: Addition of Numbers

The terms of the addition, a and b, are called addends and the result, c is the sum.