$\frac{d}{dx}y^2\cdot x^2+x\cdot y+x\cdot y^2-10$

$\frac{6}{y-2}-\frac{3}{y}=\frac{5y+2}{y^2-4}$

$\left(\sqrt{\left(3\right)}-\:x^2\right)^2$

$14r\:+\:14\:-\:r\:-\:6$

$\sqrt[3]{\left(-1\right)\left(64a^9b^3\right)\left(125c^{15}d^6\right)}$

$\frac{x^3}{4}+\sqrt{x+2z}-\frac{1}{3}y^3;\:\:x=2\:;y=3;\:z=7$

$20x+\frac{4}{5}y^{\frac{3}{5}}\text{\cdot y}^'=\frac{2}{3}x^4$