$\int\left(\frac{1}{16x^2-13}\right)dx$
$x^2-16x-63=0$
$-11b+7=40$
$-2x+y+6z=18$
$\frac{1}{4y}\cdot\frac{2}{1}$
$0.002\cdot1000$
$3.32\cdot10^4$
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