$\int\frac{x^7}{\left(x-3x^4\right)^2}dx$
$\left(2x^2\:-8y^3\right)^2$
$\frac{tan\left(4x\right)}{sec\left(4x\right)-1}$
$\frac{dy}{dx}=-6x-30$
$-1+4+-3$
$\int\frac{22}{\left(x+1\right)\left(x-4\right)}dx$
$-x^3+2x^2+9x-18$
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