$\sqrt[2]{5^2-4^2}$
$\int\frac{t^4}{\sqrt[5]{3+t^5}}dt$
$\int_{x}^{-2}dx$
$\frac{2}{x}>-4$
$\frac{5}{b^{-8}}$
$8-1\cdot25$
$\left(-2\right)\left(3\right)\left(-5\right)\left(7\right)$
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